SOLUTION: Having some trouble with this problem, any help is appreciated.
Solve the following on the interval [0,2pi]:
{{{2(cos(t))^2-cos(t)-1=0}}}
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Question 976076: Having some trouble with this problem, any help is appreciated.
Solve the following on the interval [0,2pi]:
Answer by FrankM(1040) (Show Source): You can put this solution on YOUR website!
Think for a moment that this is similar to
Which factors to
And X=1 or x= -1/2
arcCos(1) is 0 and 2pi
arcCos -1/2 is 2/3 pi or 4/3 pi
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