SOLUTION: Prove the identity.
sin (A+B) / sin (A-B) = tan A + tan B/ tan A - tan B
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Question 968325: Prove the identity.
sin (A+B) / sin (A-B) = tan A + tan B/ tan A - tan B
Answer by amarjeeth123(570) (Show Source): You can put this solution on YOUR website!
sin (A+B) / sin (A-B) =(sinA cosB+cosA sinB)/(sinA cosB-cosA sinB)
Dividing both numerator and denominator by cosA CosB
=(sinA/cosA+sinB/cosB)/(sinA/cosA-sinB/cosB)
=(tanA+tanB)/(tanA-tanB)
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