SOLUTION: Solve the following equations given that 0° ≤ θ < 360° :
A) cos θ = -((sqrt3)/2)
B) sin θ/2 - 1/2 = 0
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Question 966763: Solve the following equations given that 0° ≤ θ < 360° :
A) cos θ = -((sqrt3)/2)
B) sin θ/2 - 1/2 = 0
Answer by ikleyn(52811) (Show Source): You can put this solution on YOUR website!
A) If = then = 150° or = 210°, providing that 0° < < 360°.
B) If = 0 then = .
It implies that = 30° or = 150°. Hence, = 60° and = 2*150° = 300° satisfies the given equation, providing that 0° < < 360°.
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