SOLUTION: Hello, I need some help with a trig equation that wants me to find the solution for tan^2x+secx = 1 (0< x< 360)(<= less than or equal to). I got 0 degrees and 360 degrees, but I

Question 966066: Hello,
I need some help with a trig equation that wants me to find the solution for tan^2x+secx = 1 (0< x< 360)(<= less than or equal to). I got 0 degrees and 360 degrees, but I don't know the other answers.Any help would be greatly appreciated.Thanks!
K. Legters
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
find the solution for tan^2x+secx = 1 [0< x< 360)

lcd: cos^2(x)

2cos^2(x)-cosx-1=0
(2cosx+1)(cosx-1)=0
cosx=-1/2
x=120˚, 240˚(In quadrants II and III where cos < 0
or cosx=1
x=0
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