SOLUTION: cos5xcos2x+sin5xsin2x= -1 for x is greater or equal to 0, and less than or equal to 2pi
Algebra.Com
Question 964658: cos5xcos2x+sin5xsin2x= -1 for x is greater or equal to 0, and less than or equal to 2pi
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Use the identity,
.
.
<--
<--
<--
RELATED QUESTIONS
solve 2sinx-1= 0 for 0 is less than or equal to x less than 2pi (answered by god2012)
Solve 2 sinx + cos2x = 2sin.sinx - 1 for 0 less thAN or equal and x greater than or equal (answered by jsmallt9)
please solve the equation (x is greater than or equal to 0 and less than or equal to 2pi)
(answered by Alan3354)
solution set for cos(theta/2)=1/2 where theta is greater than or equal to 0 and less than (answered by MathLover1)
2 sin^2x+sinx=1
Find all solutions to each equation for 0 less than or equal too x... (answered by stanbon)
Please solve the equation: (x is less than or equal to 2pi and greater than or equal to... (answered by lwsshak3)
2sinx-sqrt(2)tanx=0
Solve for
angles greater than or equal to zero and less than 2pi. (answered by lwsshak3)
Please help me solve this equation:cosx+sinx=1/(cosx+sinx) for value of x such that{{{0... (answered by Fombitz)
2sin^2x-3sinx+1=0, 0 equal to or less than x... (answered by fractalier)