SOLUTION: sin2x=cosx [-pi;2pi] I don't how to explain it cause English isn't my native language but I need to solve this and the answers have to be somewhere between to values that are shown

SOLUTION: sin2x=cosx [-pi;2pi] I don't how to explain it cause English isn't my native language but I need to solve this and the answers have to be somewhere between to values that are shown

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Question 963573: sin2x=cosx [-pi;2pi] I don't how to explain it cause English isn't my native language but I need to solve this and the answers have to be somewhere between to values that are shown in brackets.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
sin2x=cosx
----------------
2sin(x)*cos(x) = cos(x)
2sin*cos - cos = 0
cos*(2sin - 1) = 0
cos(x) = 0
x = -pi/2, +pi/2, 3pi/2
----------------
2sin - 1 = 0
sin(x) = 1/2
x = pi/6, 5pi/6
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