SOLUTION: (square root of 2)(sinx)(cosx)+(cosx)=0

SOLUTION: (square root of 2)(sinx)(cosx)+(cosx)=0

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Question 961317: (square root of 2)(sinx)(cosx)+(cosx)=0
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
for: [0, 2π)
(square root of 2)(sinx)(cosx)+(cosx)=0

cosx=0
x=π/2, 3π/2
or
√2sinx+1=0
sinx=-1/√2=-√2/2
x=5π/4, 7π/4
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