SOLUTION: Find all solutions to 3sin(2x) - cosx = 0 over the interval [0,360]. Round all non-integer answers to the nearest tenth of a degree.
I know that sin 2x = 2sinxcosx so I get 3(2s
Algebra.Com
Question 957649: Find all solutions to 3sin(2x) - cosx = 0 over the interval [0,360]. Round all non-integer answers to the nearest tenth of a degree.
I know that sin 2x = 2sinxcosx so I get 3(2sinxcosx) - cosx = 0.
I just don't know what to do after that.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find all solutions to 3sin(2x) - cosx = 0 over the interval [0,360]. Round all non-integer answers to the nearest tenth of a degree.
I know that sin 2x = 2sinxcosx so I get 3(2sinxcosx) - cosx = 0.
I just don't know what to do after that.
=========================
3(2sinxcosx) - cosx = 0
6sin*cos - cos = 0
---
Factor it.
cos*(6sin - 1) = 0
cos(x) = 0
=====================
sin(x) = 1/6
RELATED QUESTIONS
Solve the equation 4sin(2theta)-3cos=0 for all values on the interval... (answered by Edwin McCravy)
Solve the equation 5cos(2a)+3=0 for all values of a on the interval 0 (answered by Theo)
Find all solutions if 0° ≤ θ < 360°. When necessary, round your answers to the (answered by lwsshak3)
Find all solutions if 0° ≤ θ < 360°. When necessary, round your answers to the (answered by Fombitz)
Find all degree solutions in the interval 0° ≤ θ < 360°. If rounding is... (answered by fractalier)
Find all degree solutions in the interval 0° ≤ θ < 360°. If rounding is... (answered by stanbon)
Find all degree solutions in the interval 0° ≤ θ < 360°. If rounding is... (answered by Theo)
Find all degree solutions in the interval 0° ≤ θ < 360°. If rounding is... (answered by ikleyn)
Find all angles in the interval [0°,360°] that satisfy the equation. Round approximations (answered by Alan3354)