SOLUTION: Sorry. Last one was screwed up. sinx/sinx+cosx = tanx/1+tanx

Algebra.Com
Question 95717: Sorry. Last one was screwed up.

sinx/sinx+cosx = tanx/1+tanx

Answer by bucky(2189)   (Show Source): You can put this solution on YOUR website!
Given:
.

.
Use the identity:
.

.
and on the right side substitute for to get:
.

.
The denominator contains 1. Replace 1 with an equivalent to make the equation
become:
.

.
Notice now that the two terms in the denominator both have the common denominator
of . Because they have the common denominator their numerators can be added over
that common denominator to get:
.

.
Note that on the right side you are dividing by the fraction
To divide by a fraction you can invert the fraction and multiply. This converts the problem
to:
.

.
On the right side cancel the terms in the denominator and numerator:
.

.
Notice that with this set of cancellations the right side now equals the left side of
the equation. Therefore, the original problem has been proven.
.
Hope this helps you to understand trig a little better.
.

RELATED QUESTIONS

-sinx/-tanx*tanx*cosx (answered by ikleyn)
(Sinx+tanx)(sinx÷1+cosx)=sinx×tanx prove the identity (answered by josgarithmetic,MathTherapy)
verify... (answered by Alan3354)
Tanx+Cosx/(1+sinx)=secx (answered by Alan3354)
(Sinx-1)(tanx+secx)=-cosx (answered by Alan3354)
prove: sinx-1/sinx =... (answered by Alan3354)
Prove the identity. sinx tanx ---- = -------- sinx+cosx (answered by edjones)
cosx+sinx-tanx/cscx (answered by Edwin McCravy)
cosx+tanx(sinx)=secx (answered by vleith)