SOLUTION: solve equation for solution (0 deg, 360 deg) 4 cos ^2 theta +4 cos theta = 1.
I used the quadratic formula, but get stuck.
Algebra.Com
Question 955450: solve equation for solution (0 deg, 360 deg) 4 cos ^2 theta +4 cos theta = 1.
I used the quadratic formula, but get stuck.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
solve equation for solution (0 deg, 360 deg) 4 cos ^2 theta +4 cos theta = 1
4cos^2(x)+4cosx=1
4cos^2(x)+4cosx-1=0
solve for cosx by quadratic formula:
a=4, b=4, c=-1
ans:
cosx=-1.207 (reject)(-1 ≤ cosx ≤1)
or
cosx=0.207
x≈78.05˚, 281.95˚
RELATED QUESTIONS
solve for solutions over the interval (0 deg, 360 deg)
4 cos^2 theta + 4 cos theta = 1
(answered by stanbon)
solve equation for solutions over the interval (0 deg, 360 deg)
cos^2 theta = sin^2... (answered by Alan3354)
Find the solution of sin2(theta)=cos(theta) if 0 deg. <= (theta) < 180... (answered by Alan3354)
Use the given information to find sin 2theta, cos 2theta, and tan 2theta.
#1) cos theta (answered by lwsshak3)
Solve the equation sin(theta)+cos(theta)= 2(sin(theta)- cos(theta)), for 0 (answered by lwsshak3,KMST)
Find the exact value of sin (theta)/2 if cos (theta) = 2/3 and 270 deg. < (theta) < 360... (answered by jsmallt9)
solve the equation for 0◦≤ x ≤ 360◦ 4-sin theta= 4 cos ^2 theta.... (answered by stanbon)
Solve the equation sqr3 sinx = 1/2 sec x for 0 deg < x < 360... (answered by lwsshak3)
The solution set for the equation {{{ Cos (theta) = -sqrt(2)/2 }}} is (135, 225 deg), use (answered by solver91311)