SOLUTION: If the point (-8,-6) is on the terminal arm of angle A in standard position, then cos(A) is? a. -4/5 b. -3/5 c. 3/5 d. 4/5 Thank you

Question 955374: If the point (-8,-6) is on the terminal arm of angle A in standard position, then cos(A) is?
a. -4/5
b. -3/5
c. 3/5
d. 4/5
Thank you
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
If the point (-8,-6) is on the terminal arm of angle A in standard position, then cos(A) is?
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cos(A) = x/r = -8/sqrt[8^2+6^2] = -8/sqrt(100) = -8/10 = -4/5
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Cheers,
Stan H.
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a. -4/5
b. -3/5
c. 3/5
d. 4/5

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