SOLUTION: If sinθ = (sqrt(7)/4) and, cos < 0.
What is tanθ?
1) (4/3)
2) -(sqrt(7)/4)
3) (sqrt(7)/3)
4) -(sqrt(7)/3)
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Question 951605: If sinθ = (sqrt(7)/4) and, cos < 0.
What is tanθ?
1) (4/3)
2) -(sqrt(7)/4)
3) (sqrt(7)/3)
4) -(sqrt(7)/3)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
If sinθ = (sqrt(7)/4) and, cos < 0.
What is tanθ?
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Note: Since sin is positive and cos is negative, theta is in QII
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By definition sin = y/4, so y = sqrt(7), r = 4
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The x = -sqrt[16-7] = -sqrt(9) = -3
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Ans: tan(t) = y/x = -sqrt(7)/3
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Cheers,
Stan H.
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1) (4/3)
2) -(sqrt(7)/4)
3) (sqrt(7)/3)
4) -(sqrt(7)/3)
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