SOLUTION: Find all solutions, showing the work, of the equation on [0,2π].
1 = cot^2 + csc x
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Question 951508: Find all solutions, showing the work, of the equation on [0,2π].
1 = cot^2 + csc x
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find all solutions, showing the work, of the equation on [0,2π].
1 = cot^2 + csc x
lcd:sin^2(x)
2sin^2(x)-sinx-1+0
(2sinx+1)(sinx-1)=0
..
2sinx+1=0
sinx=-1/2
x=π/6,11π/6
or
sinx-1=0
x=0,π,2π
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