SOLUTION: the question is : Find the exact value of cos(u/2) if sinu= -12/13 (3pi/2<u<2pi)
I got -2√13/13 does anyone know if this is correct?
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Question 950267: the question is : Find the exact value of cos(u/2) if sinu= -12/13 (3pi/2
I got -2√13/13 does anyone know if this is correct?
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
: Find the exact value of cos(u/2) if sinu= -12/13 (3pi/2
***
Identity:
sinu=-12/13 (Q4)
cosu=5/13 (working with (5-12-13) reference right triangle in quadrant IV)
=
Check:
sinu=-12/13
u=292.62
u/2=146.31
cos (u/2)=cos(146.31)≈-0.8320
exact value as computed=-3√3/13≈-0.8320
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