SOLUTION: 1/secA-tanA =secA+tanA
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Question 947390: 1/secA-tanA =secA+tanA
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
1/secA-tanA =secA+tanA
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Multiply both sides by secA-tanA to get:
1 = [sec^2(A)-tan^2(A)]
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1 = [1/cos^2 - sin^2/cos^2]
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1 = [1-sin^2]/cos^2
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1 = [cos^2/cos^2]
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1 = 1
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Cheers,
Stan H.
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