SOLUTION: Solve the equation cotangent squared of the quantity of pi over 2 minus theta = secant of theta + 1 for for theta greater than or equal to 0 but less than 2 pi.

Question 945487: Solve the equation cotangent squared of the quantity of pi over 2 minus theta = secant of theta + 1 for for theta greater than or equal to 0 but less than 2 pi.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Solve the equation cotangent squared of the quantity of pi over 2 minus theta = secant of theta + 1 for for theta greater than or equal to 0 but less than 2 pi.
***
use x for theta

lcd: cos^2(x)

2cos^2(x)+cosx-1=0
(2cosx-1)(cosx+1)=0
cosx=1/2
x=π/3,5π/3
or
cosx=-1
x=π

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