SOLUTION: Through (−1, −2);perpendicular to the line 2x + 5y + 1 = 0. What equation satisfies the conditions.

SOLUTION: Through (−1, −2);perpendicular to the line 2x + 5y + 1 = 0. What equation satisfies the conditions.

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Question 939539: Through (−1, −2);perpendicular to the line 2x + 5y + 1 = 0. What equation satisfies the conditions.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
2x + 5y + 1 = 0 0r y = (-2/5)x - 1/5
....
New Perpendicular Line: m = 5/2
***Using point-slope form, P(-1,-2)
y + 2 = (5/2)(x+1)
y = (5/2)x + 5/2 - 4/2
y = (5/2)x + 1/2
0r
5x - 2y = -2 Standard Form
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