SOLUTION: Find the sum of the first 6 terms of the following series, to the nearest integer. 
13, 26, 52
Algebra.Com
Question 935668:  Find the sum of the first 6 terms of the following series, to the nearest integer. 
13, 26, 52 
Found 2 solutions by  2897696, josgarithmetic:
Answer by 2897696(96)   (Show Source): You can put this solution on YOUR website!
 need to find 3 more terms, you are already given 3 terms of the 6
the pattern is to multiply by 2: 13*2=26*2=52*2=104*2=208*2=416*2=832
13,26,52,104,208,416
add theses numbers together and you get : 819 
Answer by josgarithmetic(39630)   (Show Source): You can put this solution on YOUR website!
 Multiples of 13.  Sequence may be .
Without using any advanced summation formulas,
 
RELATED QUESTIONS
Find the sum of the first 9 terms of the following series, to the nearest integer.... (answered by oscargut)
Find the sum of the first 6 terms of the following series, to the nearest integer.
11,  (answered by 2897696)
An arithmetic series has the following properties
(i) the sum of the fourth and ninth... (answered by greenestamps)
An arithmetic series has the following properties
(i) the sum of the fourth and ninth... (answered by rk2019,ikleyn)
Find the sum of the first n terms of the following series
  1-4+9-16+----
 (answered by solver91311)
Find the sum of the first n terms of the following series
  1x2x3+2x3x4+3x4x5x+---
 (answered by Edwin McCravy)
find the sum of the first n terms of the given arithmetic series
a1=-13,a7=20.8... (answered by stanbon)
Please find the arithmetic sum of the first 100 terms of the series... (answered by scott8148)
Find the sum of series 1+4+13+40+121 to n terms
 (answered by MathLover1)