SOLUTION: Write the expression log lower case a (y+5)+2log lower case a(x+1) as one logarithm.

Question 93513This question is from textbook Algebra and Trigonometry
: Write the expression log lower case a (y+5)+2log lower case a(x+1) as one logarithm. This question is from textbook Algebra and Trigonometry

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Write the expression log lower case a (y+5)+2log lower case a(x+1) as one logarithm.
Rule log A + log B = log AB
That means "when you add exponents you are multiplying"
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Your Problem:
log(y+5) + 2 log(x+1)
= log (y+5) + log (x+1)^2
= log [(y+5)(x+1)^2]
Note: The base on all of these is "a"
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Cheers,
Stan H.
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Please help express the below as one logarithm. log(lower a)(y+5)+ 2log(lower a)(x+1). (answered by stanbon)