SOLUTION: Proof: 2-(sin θ -cos θ )^2= (sinθ+cosθ)^2 THanks

SOLUTION: Proof: 2-(sin θ -cos θ )^2= (sinθ+cosθ)^2 THanks

Algebra.Com

Question 934716: Proof:
2-(sin θ -cos θ )^2= (sinθ+cosθ)^2
THanks
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

proof:
=
=
=
=
=...............we know
=
= since
=
=
=

RELATED QUESTIONS
2 sinθ cosθ =... (answered by Alan3354)

prove each identity tanθ -1 = sin^2θ-cos^2θ/... (answered by MathLover1)

2. For all θ where sin θ - cos θ ≠ 0, ((sin^2)(θ) -... (answered by solver91311)

(sin^2θ -tanθ)/(cos^2θ-cotθ) =... (answered by Edwin McCravy)

prove (1 / tan^2θ ) + (1 / 1+ cot^2θ) = 1 and (sinθ +... (answered by chibisan)

The expression sin θ (cot θ - csc θ) is equivalent to? A) 2 Cos θ (answered by stanbon,lynnlo)

Prove that: 2cos^3 θ-cos θ/sinθ cos^2 θ-sin^3 θ= cot... (answered by solver91311)

Prove that... (answered by Jc0110)

The expression sin θ(cotθ - cscθ) is equivalent to 1) cotθ -... (answered by stanbon)