SOLUTION: I'm struggling with rewriting sin(x-4pi/3). I know it equals sinxcos4pi/3-sin4pi/3cosx and that cos4pi/3 equals (-1/2) and that sin 4pi/3 equals (-sqrt3/2) but I don't know where

Question 933242: I'm struggling with rewriting sin(x-4pi/3). I know it equals sinxcos4pi/3-sin4pi/3cosx and that cos4pi/3 equals (-1/2) and that sin 4pi/3 equals (-sqrt3/2) but I don't know where to go from there.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
I'm struggling with rewriting sin(x-4pi/3). I know it equals sinxcos4pi/3-sin4pi/3cosx and that cos4pi/3 equals (-1/2) and that sin 4pi/3 equals (-sqrt3/2) but I don't know where to go from there.
***
sin(x-4π/3)
=sinxcos(4π/3)-cosxsin(4π/3)
=sinx*(-1/2)-cosx*(-√3/2)
=-sinx/2+√3cosx/2
=(sinx+√3cosx)/2
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