SOLUTION: 2sinx-sqrt(2)tanx=0
Solve for
angles greater than or equal to zero and less than 2pi.
Algebra.Com
Question 928884: 2sinx-sqrt(2)tanx=0
Solve for
angles greater than or equal to zero and less than 2pi.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
2sinx-sqrt(2)tanx=0
Solve for
angles greater than or equal to zero and less than 2pi.
***
sinx=0
x=0, π
or
2cosx-√2=0
cosx=√2/2
x=π/4,7π/4
RELATED QUESTIONS
solve 2sinx-1= 0 for 0 is less than or equal to x less than 2pi (answered by god2012)
Solve 2 sinx + cos2x = 2sin.sinx - 1 for 0 less thAN or equal and x greater than or equal (answered by jsmallt9)
If we have cos ( theta + (pi/4)) = sqrt(2)/2 and the range is between 0 greater than/or... (answered by josmiceli,lwsshak3)
cos5xcos2x+sin5xsin2x= -1 for x is greater or equal to 0, and less than or equal to... (answered by Fombitz)
solution set for cos(theta/2)=1/2 where theta is greater than or equal to 0 and less than (answered by MathLover1)
please solve the equation (x is greater than or equal to 0 and less than or equal to 2pi)
(answered by Alan3354)
Solve the equation for values for x greater than or equal to 0 and less than 2pi. Write... (answered by lwsshak3)
Please solve the equation: (x is less than or equal to 2pi and greater than or equal to... (answered by lwsshak3)
Please help me solve this equation:cosx+sinx=1/(cosx+sinx) for value of x such that{{{0... (answered by Fombitz)