SOLUTION: Find all solutions for, 5 sin^2(x) plus sin(x)= cos^2(x), that lie between 0 =< x =< 2pi.

Algebra.Com
Question 926175: Find all solutions for, 5 sin^2(x) plus sin(x)= cos^2(x), that lie between 0 =< x =< 2pi.

Answer by lwsshak3(11628)   (Show Source): You can put this solution on YOUR website!
Find all solutions for, 5 sin^2(x) plus sin(x)= cos^2(x), that lie between 0 =< x =< 2pi
***
5sin^2(x)+sinx=cos^2(x)
5sin^2(x)+sinx=1-sin^2(x)
6sin^2(x)+sinx-1=0
(3sinx-1)(2sinx+1)=0
3sinx-1=0
sinx=1/3
x≈0.34, 2.80
or
2sinx+1=0
sinx=-1/2
x=7π/6, 11π/6

RELATED QUESTIONS

Find all exact solutions on (0, 2pi) sec(x) sin(x) - 2 sin(x) =... (answered by Boreal,MathLover1)
Find all the solutions between 0 and 2pi to the equation... (answered by ewatrrr)
Find all solutions of each of the equations in the interval (0, 2pi) cos(x- pi/2) +... (answered by lwsshak3)
0Sin^2(x)-sin(x)= Find the possible solutions between 0 and... (answered by Cromlix)
what are all the solutions of 2cos^2(x)-cos(x)-1=0 that lie in the interval [0,... (answered by solver91311)
given that {{{cos(x) = 3/5}}}, {{{3pi/2 < x < 2pi}}} find {{{cos(x/2)}}},... (answered by Edwin McCravy)
2 sin 2x cos x + 3 sin x=0 Find all solutions in interval (0,2pi) (answered by lwsshak3)
sin(x/2) + cos(x) = 0 Give all answers From 0 to 2pi (answered by lwsshak3)
0 2pi: sin^2(x)-sq root of 3... (answered by lwsshak3)