SOLUTION: find all solutions of the equation in the interval [0,2pi) 2 sin x + csc x = 0 2 sec^2 x + tan^2 x

SOLUTION: find all solutions of the equation in the interval [0,2pi) 2 sin x + csc x = 0 2 sec^2 x + tan^2 x - 3 = 0

Question 924612: find all solutions of the equation in the interval [0,2pi)
2 sin x + csc x = 0
2 sec^2 x + tan^2 x - 3 = 0
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
find all solutions of the equation in the interval [0,2pi)
2 sin x + csc x = 0
2sin + 1/sin = 0
2sin^2 + 1 = 0
sin^2 = -1/2
x = 210, 330 degs
x = 7pi/6, 11pi/6 radians
=================
2 sec^2 x + tan^2 x - 3 = 0
sec^2 = tan^2 + 1
2tan^2 + 2 + tan^2 - 3 = 0
3tan^2 = 1
tan(x) = sqrt(3)/3
etc
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