SOLUTION: Find the exact value of sin (arccos[-2/5])
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Question 923467: Find the exact value of sin (arccos[-2/5])
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find the exact value of sin (arccos[-2/5])
(arccos[-2/5]) reads:
the angle x whose cos=-2/5
cosx=-2/5
sin(arccos[-2/5])=sinx=√(1-cos^2x)=√(1-4/25)=√(21/25)=√21/5
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