SOLUTION: Find the solution set of each of the following over the interval 0 ≤ x < 2.
1) sin x - 1= 0
2) √2 cos x + 1= 0
3) tan^2 x - 1= 0
Algebra.Com
Question 921858: Find the solution set of each of the following over the interval 0 ≤ x < 2.
1) sin x - 1= 0
2) √2 cos x + 1= 0
3) tan^2 x - 1= 0
Answer by srinivas.g(540) (Show Source): You can put this solution on YOUR website!
1)sin x-1 =0
add 1 on both sides
sin x-1+1 =0+1
sinx = 1
x =
2) cos *x +1=0
subtract 1 on both sides
cos *x +1-1 =0-1
cos *x =-1
divide with on both sides
*cos *x =-1*
cos *x =
x = 3π/4
3)
tan^2 x -1 =0
add 1 on both sides
tan^2 x-1+1=0+1
tan^2 x =1
square root on both sides
sqrt(tan^2 x ) =
tan x= 1
x = π/4
RELATED QUESTIONS
Solve the following equations given that: 0 ≤ x < 2π
(a)... (answered by Alan3354)
Find all solutions of each of the equations in the interval [0,2pi).
a)... (answered by KMST)
what is the solution set of all angles in [0,2pi)
4 cos^2x-3=0
5 sec^2x-20=0
(answered by stanbon)
Find the solution of the equation for [0,2pi]
2(tan(theta))-(sec^2(theta))=0
Here... (answered by Alan3354)
Solve the cos x-1 =0 on the interval 0≤x≤pi/2
x+ π/3
x=0
x=π/6... (answered by richard1234)
For each of the following, find all solutions. The variable n denotes a generic integer.
(answered by stanbon)
How many solutions does {{{cos(pi/5)(x+2)=-1}}} has over the interval... (answered by htmentor)
Suppose sin x =2/7,cos x > 0, sin y = − 2/5 and cos y < 0. Then
cos x=
cos y=
Find (answered by CPhill)
How would you find exact solution of sin^2(x) - 1 = 0 in the interval... (answered by lwsshak3)