Hi,
10π/3 - 2π = 4 π/3 Step I for those > 2pi
III Quadrant or (-1/2,-√3/2 )
One may view these terminal points as MINUS those in the first Quadrant for π/3
terminal points (-1/2,-√3/2 )
sec 10π/3 = 1/(-1/2) = -2
csc 10π/3 = 1/(- √3/2) = -2/√3 = -2√3/3
..........
(cosx, sinx) Summary Unit Circle
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