SOLUTION: how do i solve the equation on interval [0,2pi)
8 cos ^ 2 -4 = 0
I've been stuck on this problem for ages and if someone could please help show me the steps so i can have an
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Question 919207: how do i solve the equation on interval [0,2pi)
8 cos ^ 2 -4 = 0
I've been stuck on this problem for ages and if someone could please help show me the steps so i can have an example to work from
thank you
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
cosx = 1/√2 = √2/2
(cosx, sinx)Unit Circle Summary to Use
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