Two sides an angle of a triangle are given, determine whether the given measurements produce one triangle, two triangles or no triangle at all.
a = 10 b = 9 A = 30 degrees
Use the law of sines to determine how many possible triangles there are
10 sin B = 9 sin 30 -------- Cross-multiplying
≈
Therefore, angles are: A: , B: , and C: (180 – 30 - 27, or 180 - 57)
Now, since sin ∠B is: , another possible measure of ∠B is its reference angle: , in the 2nd quadrant.
However, ∠B CANNOT possibly be since that would result in ∠B () + ∠A () being equal to ,
which is > .
Thus, ONLY ONE (1) triangle can be formed with the given measurements