SOLUTION: solve the equation for x in the interval [0,2pi) 13 sin x = 2 cos ^2 x -8 please help explain the steps thanks in advance

Question 919034: solve the equation for x in the interval [0,2pi)
13 sin x = 2 cos ^2 x -8
please help explain the steps
thanks in advance
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
solve the equation for x in the interval [0,2pi)
13 sin x = 2 cos ^2 x -8
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