SOLUTION: How would I go about solving for amplitude, period and phase shift for:
y = 2 sin ((3/4)x − (3π)/16)
and
y = 8 cos ((3/4)x − (3π)/16)
Please ex
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Question 918419: How would I go about solving for amplitude, period and phase shift for:
y = 2 sin ((3/4)x − (3π)/16)
and
y = 8 cos ((3/4)x − (3π)/16)
Please explain how to solving these, I have no clue what I am suppose to do :/
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
How would I go about solving for amplitude, period and phase shift for:
y = 2 sin ((3/4)x − (3π)/16)
and
y = 8 cos ((3/4)x − (3π)/16)
***
Form of equation for sin function: y=Asin(Bx-C), A=amplitude, Period=2π/B, Phase shift=C/B
For given sin function:
y=2sin((3/4)x-(3π/16))
amplitude=2
B=3/4
Period=2π/B=2π/(3/4)=8π/3
C=3π/16
Phase shift=C/B=(3π/16)/(3/4)=12π/48=π/4 (shift to the right)
..
Form of equation for cos function: y=Acos(Bx-C), A=amplitude, Period=2π/B, Phase shift=C/B
For given cos function:
y=8cos((3/4)x-(3π/16))
amplitude=8
B=3/4
Period=2π/B=2π/(3/4)=8π/3
C=3π/16
Phase shift=C/B=(3π/16)/(3/4)=12π/48=π/4 (shift to the right)
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