SOLUTION: Find the exact solution to the equation in the interval [3pi/2, 5pi/2]. sin(t)= -1/2

SOLUTION: Find the exact solution to the equation in the interval [3pi/2, 5pi/2]. sin(t)= -1/2

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Question 917947: Find the exact solution to the equation in the interval [3pi/2, 5pi/2].
sin(t)= -1/2
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find the exact solution to the equation in the interval [3pi/2, 5pi/2].
sin(t)= -1/2
t=11π/6(in quadrants IV)
note: sin>0 in quadrant I which is covered by given interval
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