SOLUTION: 〖Sin〗^4 θ-〖Cos〗^4 θ=〖Sin〗^2 θ-〖Cos〗^2 θ=2〖Sin〗^2 θ-1=1-2〖Cos〗^2 θ

SOLUTION: 〖Sin〗^4 θ-〖Cos〗^4 θ=〖Sin〗^2 θ-〖Cos〗^2 θ=2〖Sin〗^2 θ-1=1-2〖Cos〗^2 θ

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Question 917680: 〖Sin〗^4 θ-〖Cos〗^4 θ=〖Sin〗^2 θ-〖Cos〗^2 θ=2〖Sin〗^2 θ-1=1-2〖Cos〗^2 θ
Answer by nihar*2013(34) (Show Source): You can put this solution on YOUR website!

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let m know if you need anymore help
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