SOLUTION: solve: cos 3x = sin x, 0 < x < pi/2 Please explain and show work, thanks!

SOLUTION: solve: cos 3x = sin x, 0 < x < pi/2 Please explain and show work, thanks!

Algebra.Com

Question 913339: solve: cos 3x = sin x, 0 < x < pi/2

Please explain and show work, thanks!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Answered
RELATED QUESTIONS
Find the exact value of sin((2x),cos(2x) given tan(x)=-9/40, -pi/2 < x < 0 Please... (answered by jsmallt9)

If f(x) = cos 2 theta + sin theta, then f (pi/2) equals 1) 1 2) 2 3) -2 4) 0... (answered by MathLover1)

"solve the following trigonometric eqaution for the given domain (cont.)": can someone... (answered by stanbon)

Solve 2 sin^2 x + cos x -2=0 on the interval -pi< x <... (answered by lwsshak3)

Please solve the equation sin*(2*x+(pi/3)) = 1/2 for x is [0,pi] Show... (answered by josmiceli)

(tough) suppose " pi/2 < 0 < pi " and " sin X = 5/16 "... Evaluate "cos... (answered by Fombitz)

Need help with question please; Given; sin (x+y) = sin x cos y+ cos x sin y and cos (x... (answered by solver91311)

sin x = cos x Solve... (answered by oscargut)

For cos(x)cos(3x)-sin(x)sin(3x)=0, use an addition or subtraction formula to simplify the (answered by ikleyn)