SOLUTION: Find the points where these conics intersect.
16𝑥^2 − 5𝑦^2 = 64 and 16𝑥^2 + 25𝑦^2 − 96𝑥 = 256
Algebra.Com
Question 911572: Find the points where these conics intersect.
16𝑥^2 − 5𝑦^2 = 64 and 16𝑥^2 + 25𝑦^2 − 96𝑥 = 256
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
1.
2.
From eq. 1,
Substitute into eq. 2,
Two solutions in x:
Then,
and
.
.
.
Then,
So the points are,
(3,4), (3,-4), and (-2,0)
RELATED QUESTIONS
Graph 𝑥^2+𝑦^2=(𝑥^2+𝑦^2−𝑥)^2
This is... (answered by Fombitz)
Find the coefficient of 𝑥5𝑦11 in the expansion of (2𝑥 −... (answered by robertb)
𝑥 − 2𝑦 + 3𝑧 = 1
−2𝑥 + 5𝑦 −... (answered by Alan3354)
Write the following equations in function notation:
a. 2𝑥 + 𝑦 = 5
b.... (answered by Boreal)
Solve the system of inequalities by graphing. (4 points)
𝑦 ≤... (answered by Boreal)
Graph 𝑥^2+𝑦^2=(𝑥^2+𝑦^2−𝑥)^2. This is from... (answered by Fombitz)
Sketch the graph of: 𝑥 = (1/4)𝑦^2 − 2𝑦 −... (answered by stanbon)
regla de cramer
𝑥 + 𝑦 + 𝑧 − 𝑤 = 2
2𝑥... (answered by ikleyn,MathLover1)
Please help with the following:
Factor: 21𝑥^2 + 11𝑥𝑦 −... (answered by josgarithmetic)