SOLUTION: Rectangle form for r^2 =-csc theta

Question 910967: Rectangle form for r^2 =-csc theta
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Rectangle form for r^2 =-csc theta
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r^2 = x^2+y^2
theta = arctan(y/x)
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So, -csc(theta) = -r/y = -sqrt(x^2+y^2)/y
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Substitute into the given equation to get:
x^2 + y^2 = -sqrt(x^2+y^2)/y
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y = -sqrt(x^2+y^2)/(x^2+y^2)
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y = -1/sqrt(x^2+y^2)
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Cheers,
Stan H.
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