SOLUTION: (1-cos^2x) / tanx → sinx*cosx
I tried with cotangent, with the 1/tanx to get cotx-cos^2x and then cotx to cosx/sinx to get cosx/sinx - cos^2 x / 1. Then multiplied by sin
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Question 908861: (1-cos^2x) / tanx → sinx*cosx
I tried with cotangent, with the 1/tanx to get cotx-cos^2x and then cotx to cosx/sinx to get cosx/sinx - cos^2 x / 1. Then multiplied by sins to have alike denominators.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(1-cos^2x) / tanx → sinx*cosx
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Note:: 1- cos^2 = sin^2
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Your Problem:
sin^2/(sin/cos) = sin*cos
----
sin^2*(cos/sin) = sin*cos
----
sin*cos = sin*cos
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Cheers,
Stan H.
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