SOLUTION: find the value of each expression: sinx= -1/2 and cosx >0 find tanx tanx = 1 and sinx <0 find cosx

Question 907590: find the value of each expression:
sinx= -1/2 and cosx >0 find tanx

tanx = 1 and sinx <0 find cosx
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
sinx= -1/2 and cosx >0 find tanx
By definition, sin = y/r
Since sin = -1/2, y = -1 and r = 2
x = sqrt(1^2 + 2^2) = sqrt(5)
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Sinc sin is negative and cos is positive, x is in QIV and is positive
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Ans: tan = y/x = -1/sqrt(5)
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tanx = 1 and sinx <0 find cosx
--
tan is positive and sin is negative in QIII; so y is negative
By definition tan = y/x
y = -1 and x = -1
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r = sqrt(1^2 + 1^2) = sqrt(2)
Ans: cos = x/r = -1/sqrt(2)
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Cheers,
Stan H.
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