SOLUTION: If 2sec2a = tanb+cotb then smallest positive value of a+b measured in degree is equal to

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Question 906268: If 2sec2a = tanb+cotb then smallest positive value of a+b measured in degree is equal to
Answer by Edwin McCravy(20060)   (Show Source): You can put this solution on YOUR website!
2sec(2a) = tan(b) + cot(b)







Divide both sides by 2









Since we are looking for small positive values
of a and b, and since the sine of one equals 
the cosine of the other, we can take 2a and 2b 
as the acute angles of a right triangle. 

So 

2a+2b = 90°

Dividing thru by 2:

a+b = 45°

Edwin
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