SOLUTION: Cosx=4/5 then tanx/[1+(tanx)^2]

Algebra.Com
Question 904892: Cosx=4/5 then tanx/[1+(tanx)^2]
Answer by lwsshak3(11628)   (Show Source): You can put this solution on YOUR website!
Cosx=4/5 then tanx/[1+(tanx)^2]
Working with a 3-4-5 right triangle
tanx=3/4
tanx/[1+(tanx)^2]
=(3/4)(1+(3/4)^2)
=(3/4)+(3/4)^3)
=3/4+27/64
=48/64+27/64
=75/64

RELATED QUESTIONS

cosxtanx +2cosx -tanx -2 ----------------------- = cosx -1 tanx... (answered by Alan3354)
If sinx+cosx = 1/2, then tanx+cotx =... (answered by tommyt3rd)
(cosx)(cscx)(tanx)=1 (answered by stanbon)
verify... (answered by Alan3354)
-sinx/-tanx*tanx*cosx (answered by ikleyn)
1-2cosx^2/sinx cosx =... (answered by Alan3354)
sinx=3/4, tanx=9/2... (answered by ewatrrr)
Tanx+Cosx/(1+sinx)=secx (answered by Alan3354)
(Sinx-1)(tanx+secx)=-cosx (answered by Alan3354)