SOLUTION: Please help..I'm struggling so much! Find the remaining trigonometric ratios of theta if cos theta = -1/3 and theta is not in QII Thank you.

Question 903323: Please help..I'm struggling so much!
Find the remaining trigonometric ratios of theta if cos theta = -1/3 and theta is not in QII
Thank you.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find the remaining trigonometric ratios of theta if cos theta = -1/3 and theta is not in QII
***
cos<0 in QII and QIII, so it must be in QIII for this problem
cos theta=-1/3
sin theta=√(1-cos^2 theta)=√(1-(-1/3)^2)=√(1-(1/9))=√(8/9)=√8/3=2√2/3
tan theta=sin theta/cos theta=-2√2
sec theta=-3
csc theta=3√2/4
cot theta=-√2/4
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