SOLUTION: Determine the vertex of y=xsquared-8x+22.

Question 90248: Determine the vertex of y=xsquared-8x+22.
Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
First determine the x-value:

Plug in b=-8 and a=1

Simplify

Lets evaluate

Start with the given polynomial

Plug in

Raise 4 to the second power to get 16

Multiply 8 by 4 to get 32

Now combine like terms

So the vertex is (4,6)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Determine the vertex of y=x^2-8x+22.
-------------
Complete the square on the x-terms and keep the equation balanced:
y = x^2-8x+(8/2)^2 +22 - (8/2)^2
y = (x-4)^2 + 88/4 - 64/4
y = (x-4)^ + 6
y-6 = (x-4)^2
Vertex at x=4,y=6
==========================

Cheers,
Stan H.

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