SOLUTION: Sketch the parabola y = -x^2 + 10x - 16 by finding only the x and y intercepts, the line of symmetry and the vertex.

Algebra.Com
Question 892254: Sketch the parabola y = -x^2 + 10x - 16 by finding only the x and y intercepts, the line of symmetry and the vertex.
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
The easy way for this one is factoring.





Zeros are at 2 and 8.
Line of symmetry is in the exact middle of those, at x=5.
The vertex is a maximum, at for the point (5,9).

RELATED QUESTIONS

Identify the vertex, axis of symmetry , y-intercept, x-intercepts, and opening of each... (answered by josgarithmetic)
y=1/2x^2+x-4 Sketch the following quadratic relationship by finding the x-intercepts (answered by greenestamps)
find the vertex, intercepts (x and y), axis of symmetry and sketch of... (answered by stanbon)
Find the line of symmetry, x intercepts, y intercept and vertex of the following... (answered by solver91311)
Find the line of symmetry, x intercepts, y intercept and vertex of the following... (answered by solver91311)
Find the line of symmetry, x intercepts, y intercept and vertex of the following equation (answered by solver91311)
Graph the function q(x)= -x^2-10x-16 by first: a) determine whether it opens up or down (answered by lynnlo)
sketch the graph of y=-4x+5 by finding the x- and y-... (answered by mananth)
Identify the line of symmetry, the vertex, the y - intercept, and the x - intercept... (answered by Cromlix)