SOLUTION: 2 cos^2 sigma sign + sin sigma symbol-2=0
interval [0,2π)
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Question 889520: 2 cos^2 sigma sign + sin sigma symbol-2=0
interval [0,2π)
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
2 cos^2 sigma sign + sin sigma symbol-2=0
interval [0,2π)
***
use x for sigma:
solve for x
2cos^x+six-2=0
2(1-sin^2x)+sinx-2=0
2-2sin^2x+sinx-2=0
-2sin^2x+sinx=0
sinx(-2sinx+1)=0
..
sinx=0
x=0
or
-2sinx+1=0
sinx=1/2
x=π/4, 3π/4
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