SOLUTION: I have a problem with a graph. Here is the link. http://s194.photobucket.com/albums/z4/dbrine/?action=view&current=t6q12.jpg

Question 88883: I have a problem with a graph. Here is the link.
http://s194.photobucket.com/albums/z4/dbrine/?action=view¤t=t6q12.jpg
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
First lets find the center:
Since the ellipse stretches from x=1 to x=9, this means the horizontal center is the average of 1 and 9. So add 1 and 9 and divide by 2

So the horizontal center is

Since the ellipse stretches from y=1 to x=7, this means the vertical center is the average of 1 and 7. So add 1 and 7 and divide by 2

So the vertical center is

So the center of the ellipse is (5,4)

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Now lets find the radii:

Now we can find the horizontal radius by subtracting 5 from 9 (this will find the distance from the horizontal center to either the left or right edge)

So the horizontal radius is 4 (ie it is 4 units from the center to the edge if you use the x-axis)

We can find the vertical radius by subtracting 4 from 7 (this will find the distance from the vertical center to either the top or bottom edge)

So the vertical radius is 3 (ie it is 3 units from the center to the edge if you use the y-axis)

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Now using the general equation of the ellipse

where (h,k) is the center, a is the horizontal radius, and b is the vertical radius

Plug in , , and (these were solved for earlier)

Square each value

Notice if we graph the equation (you need to solve for y first) we get

and this shows that our answer is correct.

So the answer is B)
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