SOLUTION: How do I find {{{ cot( sin^-1(-1/2) - sec^-1(2) ) }}}? I have {{{ x = sin^-1(-1/2)}}} implies sin x= -1/2 and {{{ y = sec^-1(2)}}} implies sec y= 2. But I'm not sure if co

Question 888015: How do I find ?
I have implies sin x= -1/2
and implies sec y= 2.
But I'm not sure if cot( x - y) is the right way to go.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
cot( sin^-1(-1/2) - sec^-1(2) )
-----
If sin(x) = -1/2, x = 210 degrees
If sec(y) = 2, y = 60 degrees
----
cot(210-60) = cot(50) = 0.8391
===================
Cheers,
Stan H.
-----------------
-------------
RELATED QUESTIONS
I nee help with 2 questions. cot (cos^-1(-5/13)) & sec (sin^-1... (answered by lwsshak3)

sec(sin^-1 x/(x... (answered by lwsshak3)

1)tan^2(x)(sin^2(x)−1)=−sin^2(x) 2) cos^2(x) = sin^2 (x) (1-csc^(x))... (answered by solver91311)

Given sin t = 1/5, sec t<0, find cos (t) and cot (t). I do not know how to find out if (answered by solver91311)

1+ Sin^2Sec^2=... (answered by stanbon)

Prove the following identity: 2 sec^2 = 1/1- sin x + 1/1+ sin... (answered by lwsshak3)

I need to equal this trig. identity 1/1 -sin = sec^2 +... (answered by xachu4u)

simplify sec^2 x(1-sin^2... (answered by htmentor)

1 + cot^2 x = sec^2x / sec^2... (answered by Alan3354)