SOLUTION: solve equation for 0 degrees < or equal to x < or equal to 360 degrees cos2x + 3sinx=2

Question 884512: solve equation for 0 degrees < or equal to x < or equal to 360 degrees
cos2x + 3sinx=2
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
solve equation for 0 degrees < or equal to x < or equal to 360 degrees
solve for x (0 < x < 360˚)
cos2x + 3sinx=2
cos^2x-sin^2x+3sinx=2
1-sin^2x-sin^2x+3sinx=2
-2sin^2x+3sinx-1=0
2sin^2x-3sinx+1=0
(2sinx-1)(sinx-1)=0
..
sinx=1/2
x=30˚, 150˚
..
sinx=1
x=90˚
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