SOLUTION: Betsy King, one of the champions of women's golf hit a ball with an initial velocity of 100 feet per second. The distance that a golf ball travels is found by the formula d= (((Vo

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Question 883406: Betsy King, one of the champions of women's golf hit a ball with an initial velocity of 100 feet per second. The distance that a golf ball travels is found by the formula d= (((Vo)^2)/g) sin2(theta) where Vo is the initial velocity, g is the acceleration due to gravity and is the measurement of the angle that the initial path of the ball makes with the ground. The acceleration due to gravity is 32ft+per+sec%5E2.
a) Write an expression for the distance the ball travels in terms of theta .
b) Find the distance Ms. King's ball travelled if the angle between the initial path of the ball and the ground measured 60°.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Betsy King, one of the champions of women's golf hit a ball with an initial velocity of 100 feet per second
The distance that a golf ball travels is found by the formula
d= (((Vo)^2)/g) sin^2(t)
where Vo is the initial velocity, g is the acceleration due to gravity and is the measurement of the angle that the initial path of the ball makes with the ground. The acceleration due to gravity is 32ft/sec^2
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a) Write an expression for the distance the ball travels in terms of "t".
d= (((Vo)^2)/g) sin^2(t)
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b) Find the distance Ms. King's ball travelled if the angle between the initial path of the ball and the ground measured 60°.
d = (100^2/32)*sin^2(60)
d = (100^2/32)*(sqrt(3)/2)^2
d = 234.375
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Cheers,
Stan H.
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