SOLUTION: cos^2 30°×cos^2 45°+4sec^2 60°+1/2cos^2 90°-2×tan^2 60°

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Question 882479: cos^2 30°×cos^2 45°+4sec^2 60°+1/2cos^2 90°-2×tan^2 60°
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

θ	radians	sin θ	cos θ	tan θ

0°	0	0	1	0

30°	π/6	1/2	√3/2	√3/3

45°	π/4	√2/2	√2/2	1

60°	π/3	√3/2	1/2	√3

90°	π/2	1	0	─

(√3/2)^2(√2/2)^2 + 4(1/(1/2))^2 + (1/2)(0)^2 - 2(√3)^2

Or (cosx,sinx) Unit circle for reference

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