SOLUTION: cos^2 30°×cos^2 45°+4sec^2 60°+1/2cos^2 90°-2×tan^2 60°

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Question 882479: cos^2 30°×cos^2 45°+4sec^2 60°+1/2cos^2 90°-2×tan^2 60°
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
θ radians sin θ cos θ tan θ
0° 0 0 1 0
30° π/6 1/2 √3/2 √3/3
45° π/4 √2/2 √2/2 1
60° π/3 √3/2 1/2 √3
90° π/2 1 0 ─
(√3/2)^2(√2/2)^2 + 4(1/(1/2))^2 + (1/2)(0)^2 - 2(√3)^2
Or (cosx,sinx) Unit circle for reference
.

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